5m^2-120=0

Solution for 5m^2-120=0 equation:

5m^2-120=0

a = 5; b = 0; c = -120;
Δ = b2-4ac
Δ = 02-4·5·(-120)
Δ = 2400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2400}=\sqrt{400*6}=\sqrt{400}*\sqrt{6}=20\sqrt{6}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{6}}{2*5}=\frac{0-20\sqrt{6}}{10}
=-\frac{20\sqrt{6}}{10}
=-2\sqrt{6}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{6}}{2*5}=\frac{0+20\sqrt{6}}{10}
=\frac{20\sqrt{6}}{10}
=2\sqrt{6}
$